Chemical Engineering - Fluid Mechanics - Discussion

Discussion Forum : Fluid Mechanics - Section 3 (Q.No. 1)
1.
Pick out the wrong statement.
The form drag is dependent upon the occurrence of a wake.
The shear stress at any given cross-section of a pipe for steady flow (either laminar or turbulent) varies linearly as the radial distance.
An ideal fluid is the one, which has negligible surface tension and obeys the Newton's law of viscosity.
Existence of the boundary layer in fluid flow is because of viscosity of the fluid.
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
5 comments Page 1 of 1.

Chayanika said:   2 months ago
Shear stress varies linearly for both laminar and turbulent.

Wherelse velocity distribution laminar is parabolic, turbulent is logarithmic or sharp pointed.

Afja said:   6 months ago
In laminar flow, shear stress varies linearly with radial distance from the centre of the pipe. Still, in turbulent flow, the relationship is more complex and does not follow a simple linear variation.

Akshay said:   3 years ago
B is also wrong. In turbulent flow, the velocity profile is constant outside the viscous sublayer, so shear stress variation should be 0.

Surya Teja said:   9 years ago
Ideal fluid does not experience surface tension or experiences negligible surface tension. But, ideal fluid is irrotational, incompressible and non-viscous. So, there is no point of talking about Newton's law of viscosity.
(1)

Vashisth said:   1 decade ago
Fluids that obey Newton's law of viscosity are known as Newtonian Fluids. For a Newtonian fluid, viscosity is entirely dependent upon the temperature and pressure of the fluid.

Examples: Water, air, emulsions.

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