Chemical Engineering - Fluid Mechanics - Discussion
Discussion Forum : Fluid Mechanics - Section 12 (Q.No. 39)
39.
A hydraulic press has a ram of 10 cms in diameter and a plunger of 1 cm in diameter. The force required on the plunger to raise a weight of 10 tons on the ram is __________ kg.
Discussion:
2 comments Page 1 of 1.
Atharva said:
6 years ago
Please someone can solve it I am not getting exactly.
Venkat said:
7 years ago
F1 = F2 (A2 / A1) = F2 (d2 / d1 )^2.
where
F1 = force on piston , kg.
F2 = force on Ram, kg.
d1 = dia of piston.
d2 = dia of ram.
10,000 = F1 *(1/10)^2.
=> F1 = 100 kg.
where
F1 = force on piston , kg.
F2 = force on Ram, kg.
d1 = dia of piston.
d2 = dia of ram.
10,000 = F1 *(1/10)^2.
=> F1 = 100 kg.
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