Chemical Engineering - Fluid Mechanics - Discussion
Discussion Forum : Fluid Mechanics - Section 10 (Q.No. 47)
47.
Hydraulic radius of 6" x 12" cross-section, is __________ inches.
Discussion:
5 comments Page 1 of 1.
TANMAY SHAH said:
2 years ago
Hydraulic radius = wetted c.s. area/wetted perimeter.
RAJKUMAR PEGU said:
3 years ago
Yes, I agreed with @Ushnish Ray.
Chem said:
8 years ago
For rectangle hydraulic radius is = 6 * 12/2(6+12).
= 2.
= 2.
(1)
Ushnish Roy said:
9 years ago
It should be 3.
As m=A/P, A = 6 * 12, P= 2*6 + 12=24 = 4 * 6.
So, m=3.
As m=A/P, A = 6 * 12, P= 2*6 + 12=24 = 4 * 6.
So, m=3.
(2)
Soni said:
9 years ago
Please explain the answer.
(1)
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