Chemical Engineering - Fluid Mechanics - Discussion
Discussion Forum : Fluid Mechanics - Section 4 (Q.No. 48)
48.
A pressure of 10 m head of water is equivalent to __________ kN/m2.
Discussion:
5 comments Page 1 of 1.
Irfan ali said:
3 years ago
Thanks everyone.
GURJAR said:
5 years ago
P = density * gravity * head.
P = 1 * 9.8 * 10.
P = 98 KN/m^2.
P = 1 * 9.8 * 10.
P = 98 KN/m^2.
(4)
Sonu MAURYA said:
6 years ago
10.3m = 101325Pa = 101325 N/m^2 = 101.325 KN/m^2.
1m = 9.834KN/m^2,
10m = 98.34 KN/m^2 approximate 98.
1m = 9.834KN/m^2,
10m = 98.34 KN/m^2 approximate 98.
Mani said:
8 years ago
Nice derivation @Chem.
Chem said:
8 years ago
p = density * gravity * head.
p = 1 * 9.8 * 10,
p = 98.
p = 1 * 9.8 * 10,
p = 98.
(2)
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