Chemical Engineering - Fluid Mechanics - Discussion
Discussion Forum : Fluid Mechanics - Section 14 (Q.No. 39)
39.
A fluid
is moving at critical flow condition (NRe = 2100) through a pipe of dia 3 cms. Velocity of flow is __________ cm/sec.

Discussion:
2 comments Page 1 of 1.
GURJAR said:
2 years ago
Given;
Kinematics viscosity= 0.01 cm²/s.
Nre= 2100.
Dia of pipe =3 cm.
Then
2100 =u× 3/0.01.
2100= u×300.
U= 2100/300.
U=7 cm/s.
Kinematics viscosity= 0.01 cm²/s.
Nre= 2100.
Dia of pipe =3 cm.
Then
2100 =u× 3/0.01.
2100= u×300.
U= 2100/300.
U=7 cm/s.
Samuel said:
1 decade ago
= 2100/3 = 700.
= 700*.01 = 7.
= 700*.01 = 7.
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