Chemical Engineering - Fluid Mechanics - Discussion
Discussion Forum : Fluid Mechanics - Section 15 (Q.No. 43)
43.
A rectangular surface 3' x 4', has the lower 3 edge horizontal and 6' below a free oil surface (sp. gr. 0.8). The surface inclination is 300 with the horizontal. The force on one side of the surface is(where, y = specific weight of water)
Discussion:
4 comments Page 1 of 1.
Chetan said:
8 years ago
0.8y*12*{6-2cos60} =48y.
Ravins said:
7 years ago
Can anyone explain it how you find the cos60?
Jomson said:
5 years ago
@Ravins.
Total angle 360.
Inclined Angle= 360-300= 60.
Total angle 360.
Inclined Angle= 360-300= 60.
Ubaid said:
4 years ago
Cos60 = 0.5
And Cos300 = 0.5.
And Cos300 = 0.5.
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