Chemical Engineering - Fluid Mechanics - Discussion
Discussion Forum : Fluid Mechanics - Section 1 (Q.No. 40)
40.
Maximum theoretical suction lift for water at 15°C by a centrifugal pump is 34 ft. The same for water at 90°C will be __________ ft.
Discussion:
14 comments Page 1 of 2.
Ahona said:
1 decade ago
What's the relation?
Div said:
1 decade ago
See the maximum theoretical suction lift for water is at 15 c is 34.
Now at 90 c, The vapour formation is taking place in water so cavitation takes place inside the pump and it lift less than the 34 ft so answer is 8.
Now at 90 c, The vapour formation is taking place in water so cavitation takes place inside the pump and it lift less than the 34 ft so answer is 8.
Asd said:
1 decade ago
Can anyone explain?
Div said:
9 years ago
Not cleared with the solution. Please explain it.
Akhil said:
9 years ago
Please anybody explain it.
Kartik said:
9 years ago
Please explain the solution.
Surya Teja said:
9 years ago
The pressure due to water should be more than the atmospheric pressure. Until and unless the pressure of water is more than atmosphere pressure pumping is possible.
1. In the first case, at 15 C, the water pressure is almost equal to the atmospheric pressure at 34 feet.
2. In the second case, at 90 C, the water pressure will be lesser than the atmospheric pressure at 34 feet. It means the height should be adjusted in such a way that the atmospheric pressure must equal the water pressure at 90 C.
Find the water pressure data from internet and calculate. As Div and I said, it will be lesser than 34 ft. But, according to my calculations, I got 24 ft. The number is wrong, but, I think, the approach is right.
1. In the first case, at 15 C, the water pressure is almost equal to the atmospheric pressure at 34 feet.
2. In the second case, at 90 C, the water pressure will be lesser than the atmospheric pressure at 34 feet. It means the height should be adjusted in such a way that the atmospheric pressure must equal the water pressure at 90 C.
Find the water pressure data from internet and calculate. As Div and I said, it will be lesser than 34 ft. But, according to my calculations, I got 24 ft. The number is wrong, but, I think, the approach is right.
(1)
Sandy said:
9 years ago
Tb/Ta = (Pb/Pa)^1-Cv/Cp
1-Cv/Cp~0.65 for water.
90/15 = (rho*g*h2/rho*g*34)^0.65
h2~8
1-Cv/Cp~0.65 for water.
90/15 = (rho*g*h2/rho*g*34)^0.65
h2~8
(6)
Gideon said:
9 years ago
Nice work guys. Thank you all.
Ramesh Vishwakarma said:
9 years ago
8 ft according to equation.
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