Chemical Engineering - Fertiliser Technology - Discussion
Discussion Forum : Fertiliser Technology - Section 1 (Q.No. 11)
11.
During conversion of ammonium carbamate into urea, presence of large excess of water
Discussion:
4 comments Page 1 of 1.
Vishal said:
2 years ago
What is the favorable conditions for the move production of NH3? Please explain to me.
Prathyusha said:
6 years ago
Ammonium carbamate is produced as an intermediate in this reactor and can then be dehydrated to urea according to the following equation:
NH2CO2NH4 -> Nh2CONH2 + H2O.
It is a reversible reaction so if large excess water is present, the reaction will move in the backward direction thus reducing the yield of urea production.
NH2CO2NH4 -> Nh2CONH2 + H2O.
It is a reversible reaction so if large excess water is present, the reaction will move in the backward direction thus reducing the yield of urea production.
(1)
Kaushal Patel said:
9 years ago
Since reaction products of ammonium carbamate are urea and water. So by Vant Hoff's equilibrium law if one of the product already available in reaction then reaction shifts from right to left (products to reactants---urea and water to ammonium carbamate). So, it decreases the yield of urea.
Adnan ahmad said:
1 decade ago
Since we need urea in they form i-e granules, so water of crystallization will form due to presence of water and thus affecting the yield of urea.
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