Chemical Engineering - Chemical Reaction Engineering - Discussion
Discussion Forum : Chemical Reaction Engineering - Section 8 (Q.No. 11)
11.
Pure A in gas phase enters a reactor 50% of this A is converted to B through the reaction, A 
3B. Mole fraction of A in the exit stream is
3B. Mole fraction of A in the exit stream isDiscussion:
7 comments Page 1 of 1.
Radhe said:
4 years ago
Mole ratio- 1/3, And mole fraction - 1/4.
Zeeshan said:
5 years ago
If 100 moles of A = 300 moles of B.
Then 50 moles of A will produce 150 moles of B then in product A will be 50/200 = 1/4.
Then 50 moles of A will produce 150 moles of B then in product A will be 50/200 = 1/4.
Yogesh Kuriya said:
6 years ago
Let assume the 100 mole of A, at the end of reaction 50% conversion means 50 moles of A produced 150 moles of B and 50 moles of A is untreated.
The total mole of mixture at exit stream is 50(A)+150(B) = 200mole.
mole fraction of A = [mole of A]/[total mole].
= 50/200.
= 0.25.
= 1/4.
The total mole of mixture at exit stream is 50(A)+150(B) = 200mole.
mole fraction of A = [mole of A]/[total mole].
= 50/200.
= 0.25.
= 1/4.
(1)
Deahenok said:
7 years ago
50/150 = 1/3 Not 50/200.
Dev said:
8 years ago
Yes, answer is 1/4. I too agree.
Sangram said:
9 years ago
Yes, I agree @Bygby.
BYGBY said:
9 years ago
Let inlet be 100 moles of A at outlet 50 mole of A 150 moles of B mole. Then the fraction will be 50/200 = 1/4.
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