Chemical Engineering - Chemical Reaction Engineering - Discussion
Discussion Forum : Chemical Reaction Engineering - Section 9 (Q.No. 9)
9.
A pollutant P degrades according to first order kinetics. An aqueous stream containing P at 2 kmole/m3 and volumetric flow rate 1m3 /h requires a mixed flow reactor of volume V to bring down the pollutant level to 0.5 kmole/m3 . The inlet concentration of the pollutant is now doubled and the volumetric flow rate is tripled. If the pollutant level is to be brought down to the same level of 0.5 kmole/m3 , the volume of the mixed flow reactor should be increased by a factor of
Discussion:
2 comments Page 1 of 1.
Nanda said:
6 years ago
Thanks @Madhuri.
Madhuri said:
9 years ago
V/1 = Cao Xa/kCao(1-Xa) = Xa/k(1-Xa)
Xa = 1-Ca/Cao = 1-0.5/2 = 0.75.
V = 0.75/kx0.25 = 3/k ------ (1).
V2/3 = Xa/k(1-Xa).
Xa = 1-Ca/Cao = 1-0.5/4 = 0.875.
V2/3 = 0.875/k(0.125) = 7/k ------(2).
Dividing (2) by (1),
(V2/3)/V = (7/k)/(3/k).
V2/3V = 7/3.
V2 = 7V.
Xa = 1-Ca/Cao = 1-0.5/2 = 0.75.
V = 0.75/kx0.25 = 3/k ------ (1).
V2/3 = Xa/k(1-Xa).
Xa = 1-Ca/Cao = 1-0.5/4 = 0.875.
V2/3 = 0.875/k(0.125) = 7/k ------(2).
Dividing (2) by (1),
(V2/3)/V = (7/k)/(3/k).
V2/3V = 7/3.
V2 = 7V.
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