Chemical Engineering - Chemical Reaction Engineering - Discussion
Discussion Forum : Chemical Reaction Engineering - Section 8 (Q.No. 40)
40.
The gas phase reaction 2A 
B is carried out in an isothermal plug flow reactor. The feed consists of 80 mole % A and 20 mole % inerts. If the conversion of A at the reactor exit is 50%, then CA/CA0 at the outlet of the reactor is
B is carried out in an isothermal plug flow reactor. The feed consists of 80 mole % A and 20 mole % inerts. If the conversion of A at the reactor exit is 50%, then CA/CA0 at the outlet of the reactor isDiscussion:
3 comments Page 1 of 1.
Vairamani said:
2 years ago
Ca/Cao = 1-Xa/1+Ea*Xa.
Ea= Xa1 - Xa0/Xa0.
Xa1= Moles of A=80=100.
Xa0= moles of B=50.
Ea= (50-80)/80 = 3/8 = 0.375.
Ca/Cao=1-0.5/(1-0.375*0.5).
= 0.5/0.8125 =0.615.
=5/8.
Ea= Xa1 - Xa0/Xa0.
Xa1= Moles of A=80=100.
Xa0= moles of B=50.
Ea= (50-80)/80 = 3/8 = 0.375.
Ca/Cao=1-0.5/(1-0.375*0.5).
= 0.5/0.8125 =0.615.
=5/8.
(1)
NITESH said:
8 years ago
The Value of Ea is -.4. So by formula, you can get the answer which is 5/8.
Dev said:
8 years ago
Ans should be A.
Ca/Cao = 1-Xa/1+ea*Xa and ea is minus 0.5 for this case.ans is 2/3.
Ca/Cao = 1-Xa/1+ea*Xa and ea is minus 0.5 for this case.ans is 2/3.
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