Chemical Engineering - Chemical Reaction Engineering - Discussion
Discussion Forum : Chemical Reaction Engineering - Section 10 (Q.No. 18)
18.
The conversion of a reactant, undergoing a first order reaction, at a time equal to three times the half life of the reaction is
Discussion:
4 comments Page 1 of 1.
Vishnu said:
4 years ago
First order conversion equation:
-ln(1-X)=Kt.
* t 1/2 for first order reaction equation.
t 1/2 = 0.693/K.
In question (time equal to three times the half life of the reaction) that means.
t = 3*t 1/2,
-ln(1-X) = K * 3 * t 1/2,
-ln(1-X) = K * 3 * 0.693/K,
-ln(1-X) = 3 * 0.693,
X = 0.875.
-ln(1-X)=Kt.
* t 1/2 for first order reaction equation.
t 1/2 = 0.693/K.
In question (time equal to three times the half life of the reaction) that means.
t = 3*t 1/2,
-ln(1-X) = K * 3 * t 1/2,
-ln(1-X) = K * 3 * 0.693/K,
-ln(1-X) = 3 * 0.693,
X = 0.875.
(3)
Bashir said:
5 years ago
Please explain it.
RAJIV KUMAR said:
8 years ago
-ln(1-XA) = 3 * 0.693,
XA = 0.8749.
XA = 0.8749.
Dalchand said:
1 decade ago
C = Co*EXP(-kt).
C = Co(1-X).
t = 3*0.693/k.
C = Co(1-X).
t = 3*0.693/k.
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