Chemical Engineering - Chemical Reaction Engineering - Discussion
Discussion Forum : Chemical Reaction Engineering - Section 1 (Q.No. 28)
28.
The rate constant of a chemical reaction increases by 100 times when the temperature is increased from 400 °K to 500 °K. Assuming transition state theory is valid, the value of E/R is
Discussion:
15 comments Page 2 of 2.
Mnnit said:
6 years ago
The Correct answer is C.
Kuldeep verma said:
6 years ago
B is the Wrong answer
Right answer is (C) 8764°K
According to transition theory.
Right answer is (C) 8764°K
According to transition theory.
Rafi said:
5 years ago
According to transition theory;
K = ko.T.e^-E/RT
And from this we get;
Ln(k2/k1) = ln(T2/T1) + E/R {1/T1 -1/T2};
As K2 = 100K1 T1=400k T2=500k;
Ln(100k1/k1) = ln(500/400) + E/R {1/400 - 1/500};
Solving this we get E/R= 8764K.
K = ko.T.e^-E/RT
And from this we get;
Ln(k2/k1) = ln(T2/T1) + E/R {1/T1 -1/T2};
As K2 = 100K1 T1=400k T2=500k;
Ln(100k1/k1) = ln(500/400) + E/R {1/400 - 1/500};
Solving this we get E/R= 8764K.
(3)
Athraa said:
3 years ago
Lnk2/lnk1 = E/R(1/T1 - 1/T2).
*k2 = 100k1.
So:
Ln100 = E/R(1÷400-1÷500).
E/R= 9210.
*k2 = 100k1.
So:
Ln100 = E/R(1÷400-1÷500).
E/R= 9210.
Ramsajan said:
2 years ago
According to transition theory answer - 8764k.
And according to Arrhenius theory, it's 9210k.
And according to Arrhenius theory, it's 9210k.
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers