Chemical Engineering - Chemical Reaction Engineering - Discussion

Discussion Forum : Chemical Reaction Engineering - Section 1 (Q.No. 36)
36.
For an isothermal variable volume batch reactor, the following relation is applicable for a first order irreversible reaction.
XA = k . t
-ln(1 - XA) = kt
εA . ln (1 - XA) = k . t
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
15 comments Page 1 of 2.

Mensah Derrick said:   7 months ago
I think option c is the correct answer.

Reason: from the general batch reactor equation, after deriving the whole equation, it will end up giving you option C as the final form.

Vipin Maurya said:   4 years ago
Agree, C is 100% correct answer.

Shubham said:   5 years ago
C is correct. I too agree.

Vishal Verma said:   7 years ago
I agree Option C is correct.

As for first-order reaction in a batch reactor, either it is constant volume or variable volume, the final expression will remain the same as given in option C.

Siddharth Pathak said:   7 years ago
Answer should be C.

Ca=Cao(1-Xa)/(1+Ea.Xa).

The term (1+Ea.Xa) cancels out from both sides when you put Ca value in rate equation for 1st order reaction.

So, integrating we still get -ln(1-Xa)=kt only.

Ashish patel said:   7 years ago
As (-r)=kCa=-dCa/dt.
Where CA=Ca0(1-Xa)/(1+EX).
Where E=epsilon.

And therefore by derivation, we got the Answer C.

Shubham Tanpure said:   8 years ago
Option B is correct. I agree with @Akshay for reference see page number 69 from octave.

Ankit said:   8 years ago
Option C is right basis on Chapter 3 octave.

Shama said:   8 years ago
I think that option C is the correct answer. Am I correct?

Santosh sahani said:   8 years ago
Option C is right.


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