Chemical Engineering - Chemical Reaction Engineering - Discussion
Discussion Forum : Chemical Reaction Engineering - Section 5 (Q.No. 4)
4.
What is the unit of the rate constant in a chemical reaction in which 10% of the reactant decomposes in one hour, 20% in two hours, 30% in three hours and so on ?
Discussion:
15 comments Page 2 of 2.
TANMAY SHAH said:
2 years ago
@All.
How can we say that this is Zero order reaction? Please, anyone explain to me.
How can we say that this is Zero order reaction? Please, anyone explain to me.
Harsh said:
2 years ago
Agree, Option A is correct according to Zero order of the reaction.
THOSIN said:
12 months ago
This reaction is a zero-order reaction because if we assume zero order, r = -dc/dt = kc^0 = k,
-dc = kdt, -c = kt + p, at t=0, c=c0, -c0 = p and -c = kt - c0.
c0 - c = kt, but c0 - c = xc0, hence, xc0 = kt and c0 = k/xt which is a linear relationship.
Since t/x is constant at any value.
Hence, for a zero-order reaction, k and r has the same unit which is moldm^-3s^-1 or mol l^-1 s^-1.
-dc = kdt, -c = kt + p, at t=0, c=c0, -c0 = p and -c = kt - c0.
c0 - c = kt, but c0 - c = xc0, hence, xc0 = kt and c0 = k/xt which is a linear relationship.
Since t/x is constant at any value.
Hence, for a zero-order reaction, k and r has the same unit which is moldm^-3s^-1 or mol l^-1 s^-1.
TANGA said:
10 months ago
Thanks @Harsh
Peprah said:
5 months ago
How is this a zero-order reaction and not a first-order reaction?
Anyone, please explain.
Anyone, please explain.
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