Chemical Engineering - Chemical Reaction Engineering - Discussion

Discussion Forum : Chemical Reaction Engineering - Section 5 (Q.No. 4)
4.
What is the unit of the rate constant in a chemical reaction in which 10% of the reactant decomposes in one hour, 20% in two hours, 30% in three hours and so on ?
Litre/mole.second
Moles/litre.second
Litre/mole
Litre/second
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
15 comments Page 1 of 2.

Peprah said:   5 months ago
How is this a zero-order reaction and not a first-order reaction?

Anyone, please explain.

TANGA said:   10 months ago
Thanks @Harsh

THOSIN said:   12 months ago
This reaction is a zero-order reaction because if we assume zero order, r = -dc/dt = kc^0 = k,
-dc = kdt, -c = kt + p, at t=0, c=c0, -c0 = p and -c = kt - c0.

c0 - c = kt, but c0 - c = xc0, hence, xc0 = kt and c0 = k/xt which is a linear relationship.

Since t/x is constant at any value.
Hence, for a zero-order reaction, k and r has the same unit which is moldm^-3s^-1 or mol l^-1 s^-1.

SATYA prakash said:   2 years ago
The unit of rate constant for zero order must be mol/lit Sec.

So, the answer is B.
(1)

Harsh said:   2 years ago
Agree, Option A is correct according to Zero order of the reaction.

TANMAY SHAH said:   2 years ago
@All.

How can we say that this is Zero order reaction? Please, anyone explain to me.

Robin Simeon said:   2 years ago
It is a zero-order reaction, So I think the correct answer is B.

Paresh said:   3 years ago
I think option B is correct.

Anandhu said:   5 years ago
B is the correct answer because it's a zero-order reaction. Unit of the rate constant is ((Moles/Litre)^1-n)/second.

Mbhuyan said:   5 years ago
B is the correct answer.


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