Chemical Engineering - Chemical Reaction Engineering - Discussion
Discussion Forum : Chemical Reaction Engineering - Section 5 (Q.No. 4)
4.
What is the unit of the rate constant in a chemical reaction in which 10% of the reactant decomposes in one hour, 20% in two hours, 30% in three hours and so on ?
Discussion:
15 comments Page 2 of 2.
Harsh said:
2 years ago
Agree, Option A is correct according to Zero order of the reaction.
SATYA prakash said:
2 years ago
The unit of rate constant for zero order must be mol/lit Sec.
So, the answer is B.
So, the answer is B.
(1)
THOSIN said:
12 months ago
This reaction is a zero-order reaction because if we assume zero order, r = -dc/dt = kc^0 = k,
-dc = kdt, -c = kt + p, at t=0, c=c0, -c0 = p and -c = kt - c0.
c0 - c = kt, but c0 - c = xc0, hence, xc0 = kt and c0 = k/xt which is a linear relationship.
Since t/x is constant at any value.
Hence, for a zero-order reaction, k and r has the same unit which is moldm^-3s^-1 or mol l^-1 s^-1.
-dc = kdt, -c = kt + p, at t=0, c=c0, -c0 = p and -c = kt - c0.
c0 - c = kt, but c0 - c = xc0, hence, xc0 = kt and c0 = k/xt which is a linear relationship.
Since t/x is constant at any value.
Hence, for a zero-order reaction, k and r has the same unit which is moldm^-3s^-1 or mol l^-1 s^-1.
TANGA said:
10 months ago
Thanks @Harsh
Peprah said:
5 months ago
How is this a zero-order reaction and not a first-order reaction?
Anyone, please explain.
Anyone, please explain.
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