Chemical Engineering - Chemical Reaction Engineering - Discussion

Discussion Forum : Chemical Reaction Engineering - Section 2 (Q.No. 36)
36.
The effect of increasing pressure on the gaseous equilibrium of the reaction 2X+3Y 3X+2Y indicates that
pressure has no effect.
backward reaction is favoured.
forward reaction is favoured.
none of these.
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
3 comments Page 1 of 1.

AKSHAY said:   5 years ago
It Don't satisfy the Le Chatelier principle.

Ashish said:   6 years ago
@Krishna.

As you know about moles increasing and decreasing. here there are no change in moles so the pressure effect will be zero.

Keq. = K * (P/P0)^-v ; where, v=overall stoichiometric coefficient.

If aA+bB=cC+dD then v=(d+c)-(a+b) ; so with this logic you can move ahead.

Hope you will understand!

Krishana said:   7 years ago
Please explain in detail.

Post your comments here:

Your comments will be displayed after verification.