Chemical Engineering - Chemical Reaction Engineering - Discussion
Discussion Forum : Chemical Reaction Engineering - Section 9 (Q.No. 26)
26.
With increase in initial concentration, the fractional conversion of a first order reaction in a given time
Discussion:
5 comments Page 1 of 1.
Verexus said:
1 year ago
For zero order, XA = k*t/[A]0.
For first order, XA = 1 - e^(-k*t).
For second order, XA = [A]0/(1+[A]0*k*t).
With the increase in [A]0 at constant t:
For zero order: XA decreases with increase in [A]0.
For the first order: XA remains constant, independent of [A]0.
For second order: XA increases with an increase in [A]0.
For first order, XA = 1 - e^(-k*t).
For second order, XA = [A]0/(1+[A]0*k*t).
With the increase in [A]0 at constant t:
For zero order: XA decreases with increase in [A]0.
For the first order: XA remains constant, independent of [A]0.
For second order: XA increases with an increase in [A]0.
Vikash ioc said:
2 years ago
For zero oder; it will be increasing.
For second order; it will be decreasing.
For first order; there will no change.
For second order; it will be decreasing.
For first order; there will no change.
(1)
KRR said:
3 years ago
For first order, ln(1-XA) = -kt.
Ankit said:
4 years ago
Hence.
t/2=(2^n-1 -1)/[(A)^n-1 (n-1)k].
For First order;
Initial concentration A =1.
t/2=(2^n-1 -1)/[(A)^n-1 (n-1)k].
For First order;
Initial concentration A =1.
Gbm said:
5 years ago
Why? Explain.
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