Chemical Engineering - Chemical Reaction Engineering - Discussion
Discussion Forum : Chemical Reaction Engineering - Section 2 (Q.No. 39)
39.
When a catalyst increases the rate of forward reaction, the value of rate constant
Discussion:
7 comments Page 1 of 1.
Pawan Kumar Sharma said:
2 years ago
A catalyst increases the rate of a reaction by decreasing the activation (Ea) energy needed for the reactions.
According to Arrhenius's equation
k=Ae−Ea/RT
When Ea decreases, (−Ea/RT) increases.
this causes e−Ea/RT to increase, and thus rate constant k increases.
According to Arrhenius's equation
k=Ae−Ea/RT
When Ea decreases, (−Ea/RT) increases.
this causes e−Ea/RT to increase, and thus rate constant k increases.
(2)
Chayanika said:
2 years ago
K is only affected by temperature.
K- is also known as the temperature-dependent term.
Catalysts don’t affect any factors. It just enhances the rate of reaction.
K- is also known as the temperature-dependent term.
Catalysts don’t affect any factors. It just enhances the rate of reaction.
Terefe Tadesse said:
2 years ago
C is the correct answer because the rate constant depends only on temperature.
Dinesh said:
4 years ago
A is correct, because it is asked for rate constant not equilibrium constant.
(3)
Antish said:
4 years ago
A is the correct answer because Catalysts/enzymes help a system to achieve its equilibrium faster, but does not alter the position of the equilibrium. Finally, Catalysts/enzymes increase k (rate constant, kinetics), but do not alter Keq (equilibrium).
(1)
SHUBHAm said:
6 years ago
A is correct. Check with Arrhenius's law.
Abebe Ethiopia said:
7 years ago
C is the correct answer because rate constant is not affected by the catalyst.
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers