Chemical Engineering - Chemical Reaction Engineering - Discussion
Discussion Forum : Chemical Reaction Engineering - Section 1 (Q.No. 4)
4.
The fractional volume change of the system for the isothermal gas phase reaction, A 
3B , between no conversion and complete conversion is
3B , between no conversion and complete conversion isDiscussion:
6 comments Page 1 of 1.
Mongam Damodhar Rao said:
11 months ago
V/vo = 1 + 0 (for no conversion).
V/vo = 1 + 2 =3(for complete conversion).
Given the question asking for change so;
∆V/vo = 3 - 1 = 2.
V/vo = 1 + 2 =3(for complete conversion).
Given the question asking for change so;
∆V/vo = 3 - 1 = 2.
Gani said:
1 decade ago
This is a gas phase reaction density is not constant.
So e = [Total no of moles of products-Total no of moles of reactants]\Total no of moles of reactants.
So e = [Total no of moles of products-Total no of moles of reactants]\Total no of moles of reactants.
(1)
Jaydeep jani said:
1 decade ago
V = V0(1+(volm at 100% conversion-volm at 0% conversion)/volm at 100% conversion)Xa).
Put Xa=1.
Then,
V = 3V0.
So fractional value changes from 1 to 3.
Put Xa=1.
Then,
V = 3V0.
So fractional value changes from 1 to 3.
(1)
Sudip chowra said:
1 decade ago
Use volume expansion factor.
[(volm at 100% conversion-volm at 0% conversion)/volm at 100% conversion]
[(volm at 100% conversion-volm at 0% conversion)/volm at 100% conversion]
(1)
Surendra.D said:
1 decade ago
The answer is 2: Because one mole of A gives 3 moles of B. And here don't give any conversion fractions. So we are simply use the formula product moles-reactant moles. After divide with reactant moles.
(2)
K.srijanya said:
1 decade ago
The answer is 2, A---->3B HERE A REACTANT(input) B PRODUCT(output) SO WE HAVE A FORMULA (output-input)/input
By this we can get like (3-1)/1 = 2.
By this we can get like (3-1)/1 = 2.
(7)
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