Chemical Engineering - Chemical Reaction Engineering - Discussion
Discussion Forum : Chemical Reaction Engineering - Section 3 (Q.No. 2)
2.
The rate of the chemical reaction A 
B doubles as the concentration of A i.e.., CA is doubled. If rate of reaction is proportional to CAn, then what is the value of n for this reaction ?
B doubles as the concentration of A i.e.., CA is doubled. If rate of reaction is proportional to CAn, then what is the value of n for this reaction ?Discussion:
3 comments Page 1 of 1.
Ankit saini said:
4 years ago
r1=k(A)^n -------> 1
r2=2r1=k(2A)^n -------> 2.
Eqn(2)/(1).
2 = 2^n.
n = 1. Ans.B.
r2=2r1=k(2A)^n -------> 2.
Eqn(2)/(1).
2 = 2^n.
n = 1. Ans.B.
(1)
Jomson Mathachan said:
6 years ago
-2ra = k 2 Ca ^n ----> (1).
-ra = kCa^n ----> (2).
Eqn (1)/(2)
2 = 2^n.
Take log on both sides, get n=1.
-ra = kCa^n ----> (2).
Eqn (1)/(2)
2 = 2^n.
Take log on both sides, get n=1.
Bilal said:
7 years ago
How the answer is 1? Please explain.
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