Chemical Engineering - Chemical Reaction Engineering - Discussion

Discussion Forum : Chemical Reaction Engineering - Section 2 (Q.No. 34)
34.
A first order reaction requires two unequal sized CSTR. Which of the following gives higher yield ?
Large reactor followed by smaller one.
Smaller reactor followed by larger one.
Either of the arrangement (a) or (b) will give the same yield.
Data insufficient, can't be predicted.
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
7 comments Page 1 of 1.

Taisir said:   3 months ago
Final Answer:

Large reactor followed by a smaller one.
Performance of CSTRs in Series:

In a CSTR, the concentration drops abruptly from the inlet to the outlet.
For first-order reactions, the conversion increases with residence time.
When placing two CSTRs in a series:

The first reactor sees the highest reactant concentration, so it contributes more to overall conversion.
Therefore, placing the larger volume reactor first leads to better performance because it exploits the high initial concentration, where the rate is highest.

Chayanika said:   2 years ago
When n>1, PFR-small CSTR-large CSTR. Prefer late mixing.
When n<1, Big CSTR-small CSTR- PFR.

Prefer early mixing.
N=1 (FIRST order) - any arrangement can be followed.
(1)

Ashish Singh said:   5 years ago
Option B is right, for +ve order small followed by large.

SHUBHAM said:   6 years ago
C is the correct answer. Option B is for, order >1.

Vikas said:   6 years ago
Correct answer is B.

Smaller CSTR followed by larger will give higher yield and conversion.

Eswar said:   8 years ago
It is independent on concentration.

Mohit said:   9 years ago
Option B is the correct answer.

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