Chemical Engineering - Chemical Process - Discussion

Discussion Forum : Chemical Process - Section 1 (Q.No. 1)
1.
Oxidation of SO2 to SO3 is favoured by
low temperature and low pressure.
low temperature and high pressure.
high temperature and low pressure.
high temperature and high pressure.
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
4 comments Page 1 of 1.

Chandan Chaudhary said:   3 years ago
According to the Le-Chatlier principle, exothermic reactions are favored at low temperatures. The number of moles' are decreasing in reaction. Such reactions, according to the Le-Chateler principle are favored at high' pressure'. This reaction will give maximum yield at reduced temperature and high pressure.
(3)

Chandu said:   9 years ago
According to Le-chatelier's principle here left to right no of moles decrease.

On increasing pressure the reaction shift where the number of mole decrease.

Pankaj said:   1 decade ago
Oxidation of SO2 +O2= SO3 is exothermic reaction reaction.

To increase SO3 concentration temperature to be kept low says by Le-chatelier's principle.

On increasing pressure the reaction shift where the number of mole decrease.
(1)

Ashok salehittal said:   1 decade ago
Oxidation reaction takes place by addition reaction, So3 in unstable state it require pressure to with hold, hence it require higher pressure.
(3)

Post your comments here:

Your comments will be displayed after verification.