Chemical Engineering - Chemical Engineering Thermodynamics - Discussion
Discussion Forum : Chemical Engineering Thermodynamics - Section 10 (Q.No. 4)
4.
Air enters an adiabatic compressor at 300K. The exit temperature for a compression ratio of 3, assuming air to be an ideal gas (Y = Cp/Cv = 7/5) and the process to be reversible, is
Discussion:
2 comments Page 1 of 1.
Anomie said:
11 months ago
@ Shruti,
V1/V2 is 3 not the inverse of it.
V1/V2 is 3 not the inverse of it.
Shruti said:
1 decade ago
In an adiabatic process:
TV^(y-1) = Constant.
So using T1*V1^(y-1) = T2*V2^(y-1).
T2 = T1*(V1/V2)^(y-1).
= 300*(1/3)^(7/5-1) (given V2/V1=3).
= 300*(1/3)^(2/5).
This should be the correct answer. But none of the options match this answer.
Option[A] would be the correct answer if we take the ratio P2/P1 = 3.
TV^(y-1) = Constant.
So using T1*V1^(y-1) = T2*V2^(y-1).
T2 = T1*(V1/V2)^(y-1).
= 300*(1/3)^(7/5-1) (given V2/V1=3).
= 300*(1/3)^(2/5).
This should be the correct answer. But none of the options match this answer.
Option[A] would be the correct answer if we take the ratio P2/P1 = 3.
(6)
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers