Chemical Engineering - Chemical Engineering Thermodynamics - Discussion

Discussion Forum : Chemical Engineering Thermodynamics - Section 10 (Q.No. 26)
26.
A gas performs the maximum work, when it expands
non-uniformly
adiabatically
isobarically
isothermally
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
10 comments Page 1 of 1.

Chayanika said:   5 months ago
Isothermally is right answer.

Because at a constant temperature, expansion occurs and internal energy is zero. So all heat is converted to work.

Dino said:   10 months ago
Yes, you are right @Max.

The area under the curve for an expansion process is the largest for an isobaric expansion in a PV diagram. So, C is correct.

Max said:   10 months ago
@Ritik.

We know that the area under the curve of a PV diagram is the work.

An isobaric expansion process on the PV diagram will appear as a horizontal line and have a larger area than either isothermal or adiabatic expansion, which slopes downward (if you can't visualize what I'm trying to say, take the PV diagram of a Carnot cycle).

Ritik said:   12 months ago
Isothermal is the right Answer because in the PV diagram Area under the curve for Isothermal is more than that of the adiabatic process.

Pawan Kumar Sharma said:   2 years ago
I agree with you, Thanks @ Flowi.

Flowi said:   3 years ago
The Isobaric, isothermal and adiabatic processes are represented in P&V as the following.

Since, the area under the P/V plot for isobaric process is more than the isothermal and adiabatic process the work done in isobaric process is highest.
(2)

Mbhuyan said:   4 years ago
Isothermally is the correct answer.

Anish said:   6 years ago
Isothermal is the right answer because of the internal energy change caused by work done only.

Deepak said:   7 years ago
Isothermally is the right answer.

Vimal said:   8 years ago
Why? can anyone explain?

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