Chemical Engineering - Chemical Engineering Thermodynamics - Discussion
Discussion Forum : Chemical Engineering Thermodynamics - Section 2 (Q.No. 43)
43.
An ideal gas is taken around the cycle ABCA as shown in P-V diagram below :
The work done by the gas during the cycle is equal to
The work done by the gas during the cycle is equal to
Discussion:
4 comments Page 1 of 1.
Khushbu chaudhary said:
1 decade ago
Work done = Area under the curve.
= 1/2*b*h ( for triangle).
= 1/2*3p1*2v1.
= 3p1v1.
= 1/2*b*h ( for triangle).
= 1/2*3p1*2v1.
= 3p1v1.
(5)
Ashu said:
8 years ago
Thanks @Khushbu.
(1)
Mele said:
6 years ago
p1 means 4p1-p1 = 3p1.
And v1 means 3v1-v1= 2v1.
Therefore, the work done for ABC mean area of ABC.
And v1 means 3v1-v1= 2v1.
Therefore, the work done for ABC mean area of ABC.
(1)
Anomie said:
12 months ago
How does height become 2v1? Please explain to me.
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