Chemical Engineering - Chemical Engineering Thermodynamics - Discussion

Under reversible conditions, the adiabatic work done is always less than the isothermal work done; this is because, in an adiabatic process, the system uses its internal energy to expand, causing a temperature drop, while in an isothermal process, the temperature remains constant, allowing for more work to be done by the system at a consistent temperature.

Irreversible work is always more than reversible work, so I think option A is incorrect.

The Adiabatic is steeper than isotherms and therefore area under PV for isotherm is bigger under the same deltaP and deltaV.

By virtue of elimination:

Reversible work is always greater than irreversible.

Heat and work are not state functions.

Energy can be exchanged as work and heat in a closed system.