Chemical Engineering - Chemical Engineering Thermodynamics - Discussion

Discussion Forum : Chemical Engineering Thermodynamics - Section 5 (Q.No. 36)
36.
The value of Joule-Thomson co-efficient, in case where cooling occurs after the throttling process is
0
+ve
-ve
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
2 comments Page 1 of 1.

Kartik said:   2 years ago
The answer should be negative because gas will cool down during the throttling process molecules are doing work to cover repulsive intermolecular force, causing them to move further apart.

Pawan Kumar Sharma said:   2 years ago
For an ideal gas, μ = 0, because ideal gases are neither warm nor cool upon being expanded at constant enthalpy.

If μ is +ve, then the temperature will fall during throttling.

If μ is -ve, then the temperature will rise during throttling.
(2)

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