Chemical Engineering - Chemical Engineering Thermodynamics - Discussion
Discussion Forum : Chemical Engineering Thermodynamics - Section 4 (Q.No. 10)
10.
What is the number of degrees of freedom for liquid water in equilibrium with a mixture of nitrogen and water vapor ?
Discussion:
5 comments Page 1 of 1.
Manu said:
3 years ago
What if nitrogen was also in a gaseous state. Will then the number of phases be 1?
Yadav said:
7 years ago
F = C-P+2.
= 2-2+2.
= 2.
= 2-2+2.
= 2.
Er Praveen Khorwal said:
7 years ago
F= 2+N-P.
F= 2+2-2,
F=2.
F= 2+2-2,
F=2.
Fds said:
8 years ago
f = c-p+1.
f = 2-1+1,
f = 2.
f = 2-1+1,
f = 2.
Hafiz Nabeel Ahamd said:
10 years ago
F = 2 - P + C.
P = phases = 2.
C = component = 2.
F = 2 -2 + 2 = 2.
F= 2.
P = phases = 2.
C = component = 2.
F = 2 -2 + 2 = 2.
F= 2.
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