Chemical Engineering - Chemical Engineering Thermodynamics - Discussion

Discussion Forum : Chemical Engineering Thermodynamics - Section 1 (Q.No. 21)
21.
Entropy of an ideal gas depends upon its
pressure
temperature
both (a) & (b)
neither (a) nor (b)
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
4 comments Page 1 of 1.

Raj musale said:   1 decade ago
Entropy of ideal gas is function of both temperature and pressure since.

Delta S = Cp ln(T2/1)-R ln(P2/P1).

Besides as gas behaves ideal at low pressure and high temperature.

So Enthalpy is very weak function of pressure and strong function of temperature.
(1)

Surya said:   1 decade ago
Entropy of an ideal gas is defined as:

delta S= (nCv ln(T2/T1))+(nR ln(V2/V1)).

or

delta S= (nCv ln(P2/P1))+(nR ln(V2/V1)) .

Since P and T are related by as P/T= constant for ideal gas.

Prasad gampala said:   8 years ago
Entropy is a measure of disorder ness of molecules. For crystalline material entropy is zero. Example ice cube.
In the ice cube the arrangement of molecules are in uniform manner, so entropy is zero.
If you heat the ice cube the arrangement of molecules will change and the value of entropy will increases.
So here temperature is one factor and same as pressure also one factor.
So entropy is depend on both temp and presusre.

John said:   4 years ago
Only B is the correct option.

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