Chemical Engineering - Chemical Engineering Thermodynamics - Discussion
Discussion Forum : Chemical Engineering Thermodynamics - Section 8 (Q.No. 12)
12.
COP of a refrigerator drawing 1 kW of power per ton of refrigeration is about
Discussion:
2 comments Page 1 of 1.
NISHAD TRIBHUWAN said:
4 years ago
COP of Ref.=(Refrigeration effect÷Work input).
So, as we know. 1 ton of refrigeration = 12000 BTU/hr. = {(12000 * 1055)÷3600} joule/s = 3516.66
Watt = 3.516 KW.
Now COP = 3.516 Kw÷1 Kw = 3.516.
The final answer is 3.516.
So, as we know. 1 ton of refrigeration = 12000 BTU/hr. = {(12000 * 1055)÷3600} joule/s = 3516.66
Watt = 3.516 KW.
Now COP = 3.516 Kw÷1 Kw = 3.516.
The final answer is 3.516.
(1)
KALAIARASI N said:
5 years ago
COP = Q2/W.
Q2 = 1TON = 12660 KJ/H = 3516.67W.
W = 1000.
COP = 3516.67/1000 = 3.52.
Q2 = 1TON = 12660 KJ/H = 3516.67W.
W = 1000.
COP = 3516.67/1000 = 3.52.
(2)
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