Chemical Engineering - Chemical Engineering Thermodynamics - Discussion

Discussion Forum : Chemical Engineering Thermodynamics - Section 11 (Q.No. 23)
23.
When a system is in equilibrium for all possible processes, the differential or finite change of entropy is
< 0
> 0
= 0
none of these
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
4 comments Page 1 of 1.

Baghel said:   2 years ago
At equilibrium, the system has reached a state where its entropy is maximized, and any further changes do not result in a net increase or decrease in entropy.

Therefore,
ΔS = 0.

Pawan Kumar Sharma said:   2 years ago
For a spontaneous process of a system, the change in entropy should be always greater than zero and for an equilibrium (more or less reversible) process the entropy must be equal to zero.

So, option C is right.

Chemi said:   9 years ago
Answer should be c) = 0.

Chemical said:   1 decade ago
When a system is in equilibrium, the entropy of the system is at a maximum with respect to any any possible changes in the system.

This means that the differential dS = 0, and any finite change in the state of the system would lead to a decrease (or not change) in entropy, so =< 0.

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