Chemical Engineering - Chemical Engineering Thermodynamics - Discussion
Discussion Forum : Chemical Engineering Thermodynamics - Section 2 (Q.No. 6)
6.
What is the value of ln y (where y = activity co-efficient) for ideal gases ?
Discussion:
5 comments Page 1 of 1.
Ramsajan paswan said:
2 years ago
Activity confusion(Y) for ideal gas = 1 then the value of ln(1) =0.
Vipin said:
6 years ago
It should be unity zero will be value of lny.
Ankit said:
7 years ago
Y=1 for ideal and pure gas.
Rohit said:
9 years ago
It should be Unity.
Pooja said:
1 decade ago
Y=1 for ideal gas.
So lnY = 0.
So lnY = 0.
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