Chemical Engineering - Chemical Engineering Thermodynamics - Discussion

Discussion Forum : Chemical Engineering Thermodynamics - Section 5 (Q.No. 50)
50.
In case of a reversible process (following pvn = constant), work obtained for trebling the volume (v1 = 1 m3 and v2 3 m3 ) is max imum, when the value of 'n' is
0
1
y = 1.44
1.66
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
2 comments Page 1 of 1.

Dinesh said:   4 years ago
It should be 1 because maximum work done is obtain at isothermal process.

Pawan Kumar Sharma said:   2 years ago
According to me, the Given answer is correct according to the use of the work done equation for the adiabatic process.

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