Chemical Engineering - Chemical Engineering Thermodynamics - Discussion
Discussion Forum : Chemical Engineering Thermodynamics - Section 6 (Q.No. 44)
44.
In a reversible process
Discussion:
2 comments Page 1 of 1.
Pawan Kumar Sharma said:
2 years ago
Yes, Option A is correct. With the help of 1st and 2nd law combination.
John said:
3 years ago
B is Correct.
TdS = dU + PdV or dU-dW.
TdS = dU + PdV or dU-dW.
(1)
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