Chemical Engineering - Chemical Engineering Thermodynamics - Discussion
Discussion Forum : Chemical Engineering Thermodynamics - Section 1 (Q.No. 29)
29.
Degress of freedom at triple point will be
Discussion:
4 comments Page 1 of 1.
Senthil Kumar M said:
1 decade ago
According to Phase rule,
F=C-P+2
Here,
C is No. of Components
P is No. of Phases
So, F=1-3+2
F=0.
F=C-P+2
Here,
C is No. of Components
P is No. of Phases
So, F=1-3+2
F=0.
(1)
Yadav said:
7 years ago
Zero is the correct answer.
Kingsley said:
4 years ago
Thanks @Senthil Kumar.
Gemedo said:
2 years ago
The Degree of freedom is;
Dof = C - P + 2.
Where C is the number of components and
P is the number of phases
Then Dof=C-P+2.
At the critical point, three states of matter coexist which is so P=3.
C = 1.
Dof = C - P + 2,
=1 - 3 + 2.
=0.
Dof = C - P + 2.
Where C is the number of components and
P is the number of phases
Then Dof=C-P+2.
At the critical point, three states of matter coexist which is so P=3.
C = 1.
Dof = C - P + 2,
=1 - 3 + 2.
=0.
(4)
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers