Chemical Engineering - Chemical Engineering Thermodynamics - Discussion
Discussion Forum : Chemical Engineering Thermodynamics - Section 3 (Q.No. 27)
27.
Compressibility factor of a gas is
Discussion:
3 comments Page 1 of 1.
Niharika said:
1 decade ago
Why is option A correct?
Z=1 for an ideal gas i.e. follows PV = nRT.
So, option D should be correct.
Z=1 for an ideal gas i.e. follows PV = nRT.
So, option D should be correct.
Chemi said:
9 years ago
Z = pv/rt, so it is dependent and option D is correct.
Ravindra sahani said:
7 years ago
Z =1 for an ideal gas i.e. follows PC=nRT.
So, the option D is correct.
So, the option D is correct.
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