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Chemical Engineering - Chemical Engineering Thermodynamics

Exercise : Chemical Engineering Thermodynamics - Section 4
46.
In an irreversible process
Tds = dE - dW = 0
dE - dW - Tds = 0
Tds - dE + dW< 0
Tds - dT + dW< 0
Answer: Option
Explanation:
No answer description is available. Let's discuss.
47.
What is the number of degree of freedom for a system of two miscible non-reacting species in vapor-liquid equilibrium forming an azeotrope ?
3
2
1
0
Answer: Option
Explanation:
No answer description is available. Let's discuss.
48.
The entropy change in a reversible isothermal process, when an ideal gas expands to four times its initial volume is
R loge 4
R log10 4
Cv log10 4
Cv loge 4
Answer: Option
Explanation:
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49.
PVγ = Constant (where, γ = Cp/Cv) is valid for a/an __________ process.
isothermal
isentropic
isobaric
adiabatic
Answer: Option
Explanation:
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50.
Claude gas liquefaction process employs cooling
at constant pressure.
by throttling.
by expansion in an engine.
none of these.
Answer: Option
Explanation:
No answer description is available. Let's discuss.
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