Chemical Engineering - Chemical Engineering Plant Economics - Discussion
Discussion Forum : Chemical Engineering Plant Economics - Section 2 (Q.No. 23)
23.
A present sum of Rs. 100 at the end of one year, with half yearly rate of interest at 10%, will be Rs.
Discussion:
4 comments Page 1 of 1.
Anand kumar said:
8 years ago
The correct answer is A=121. Because.
Rate=p(1+r/100)^n
= 100(1+10/100)^2.
= 100(11/10)^2.
= 100*121/100.
= 121.
If give the half-yearly then time will be two times of times, hence n=2*1=2.
Rate=p(1+r/100)^n
= 100(1+10/100)^2.
= 100(11/10)^2.
= 100*121/100.
= 121.
If give the half-yearly then time will be two times of times, hence n=2*1=2.
Dipankar Kakati said:
9 years ago
The correct answer should be Rs. 110.25/.
(1)
Ravi gupta said:
5 years ago
P * (1+R/200)^2 is the correct formula.
Akash said:
7 years ago
Yes, right agree @Dipankar.
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