Chemical Engineering - Chemical Engineering Plant Economics - Discussion
Discussion Forum : Chemical Engineering Plant Economics - Section 1 (Q.No. 16)
16.
Accumulated sum at the end of 5 years, if Rs. 10000 is invested now at 10% interest per annum on a compound basis is Rs.
Discussion:
5 comments Page 1 of 1.
Sunil Chunduru said:
6 years ago
S = P(1+ i)^n.
S = 10000(1+0.1)^5.
S = 16105.1.
S = 10000(1+0.1)^5.
S = 16105.1.
(1)
Sandesha said:
9 years ago
Interest per year will be 1000. So after 5 years it will be 5000.
Hence 10k + 5k = 15K.
Can you explain the above answer?
Hence 10k + 5k = 15K.
Can you explain the above answer?
Vishal said:
9 years ago
@Sandesha.
The question is specified with a term "compound basis".
The question is specified with a term "compound basis".
M.P.SINGH said:
9 years ago
A = P(1 + R/100)^5.
A = 10000(1 + 10/100)^5.
A = 10000 * (1.1)^5.
A = 16105.
A = 10000(1 + 10/100)^5.
A = 10000 * (1.1)^5.
A = 16105.
Borsadiya tushar said:
5 years ago
A = P(1+R/100)^5,
A = 10000(1+10/100)^5,
A = 10000*(1.1)^5,
A = 16105.
A = 10000(1+10/100)^5,
A = 10000*(1.1)^5,
A = 16105.
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