Chemical Engineering - Chemical Engineering Basics - Discussion
Discussion Forum : Chemical Engineering Basics - Section 22 (Q.No. 42)
42.
Maximum heat dissipation occurs from a steel wire (k = 0.5 W/m. k) of 15 mm diameter exposed to air (h = 20W/m2 .k), when the insulation thickness is __________ mm.
Discussion:
1 comments Page 1 of 1.
Shyam said:
3 years ago
For maximum heat dissipation, the thickness of insulation should be its critical thickness.
The critical thickness for wire is given as,
Calculation:
Given:
k = 0.5 W/mK, h = 20 W/m2K.
The thickness of insulation = rc - r.
The critical thickness for wire is given as,
Calculation:
Given:
k = 0.5 W/mK, h = 20 W/m2K.
The thickness of insulation = rc - r.
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