Chemical Engineering - Chemical Engineering Basics - Discussion
Discussion Forum : Chemical Engineering Basics - Section 28 (Q.No. 2)
2.
For a spontaneous natural process at constant temperature and pressure, the free energy of the system always
Discussion:
4 comments Page 1 of 1.
Kartheek said:
6 years ago
Negative, the process is spontaneous and may proceed in the forward direction as written.
Positive, the process is non-spontaneous as written, but it may proceed spontaneously in the reverse direction.
Zero, the process is at equilibrium, with no net change taking place over time.
Positive, the process is non-spontaneous as written, but it may proceed spontaneously in the reverse direction.
Zero, the process is at equilibrium, with no net change taking place over time.
Swapnil z said:
1 decade ago
Any spontaneous process in a system at constant T and p must decrease the Gibbs free energy (if the system is away from equilibrium) or leave the Gibbs free energy unchanged (if the system is at equilibrium).
Swarup said:
3 years ago
I think the answer will be "decreases".
Nanda said:
7 years ago
Right @Swapnil.
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