# Chemical Engineering - Chemical Engineering Basics - Discussion

15.

The boiling & freezing points on a newly defined temperature scale in degree 'D' are 400°D & 100°D respectively. The temperature reading corresponding to 60°C on this new temperature scale will be equal to __________ °D.

 [A]. 140 [B]. 180 [C]. 240 [D]. 280

Explanation:

No answer description available for this question.

 Xyz said: (Aug 27, 2014) Calibration of any temperature scale is done by some standard samples like WATER. Here B.P. and M.P. of water is 100 and 0 degree Celsius respectively. So 400*D = 100*C & 100*D = 0*C so for each 1*Celsius=3*D, So 60*C = 100*D+(3*60)*D = 280.

 Shafeeq said: (Oct 3, 2016) 100 * C = 400 * D. 60 * C = 400 x 60/100 = 240 * D.

 Brt said: (Feb 10, 2017) 240 is the right answer.

 Mounika said: (Dec 2, 2017) 1*C = 4*D. So 60*C = 60*4=240*D. 240 is right answer.

 Ruwin said: (Sep 16, 2018) Check the accuracy of result by computing the equivalent of °D at 0°C. 1. 400°D = 100°C. X°D. =. 0°C. (400-100)°D/(100-0)°C=3°D/1°C. General formula: (400 - °D)/(100 - °C)=3/1. (400 - °D) = 3x (100 - °C), °D = 400 - 3 x (100 - °C), So for 60°C °D = 400 - 3 x (100 - 60), °D = 400 - 3 x (40), °D = 400 - 120, °D = 280. If 0°C °D = 400 - 3 x (100 - 0), °D = 400 - 3 x (100), °D = 400 - 300, °D = 100°D.

 Jitendra Yadav said: (Jan 6, 2019) According to thermometric property. Tn= a + bTc. where Tn=N scale ; Tc=deg celcius scale. Ice point : 100= a+b(0).(1). Steam point : 400= a+b(100).(2). Solving eqn. 1 & 2 , we get , a=100 b=3. Corresponding to 60deg celcius , Tn= 100+3(60) =280 N [ans:D].

 Saurabh said: (Apr 17, 2020) The new scale is 100D --- 400D. So the difference is 300D: 300D is the total measuring scope of the new scale. 60C= 100+300*60/100 (why added 100 because the new scale starting at 100D) That's why 60C =100+ 180. 60C= 280D.

 Mbhuyan said: (Dec 20, 2020) (D-100)/(400-100) = (60-0)/(100-0). (D-100)/300 = 60/100, D = 180 + 100, = 280.