Chemical Engineering - Chemical Engineering Basics - Discussion
Discussion Forum : Chemical Engineering Basics - Section 8 (Q.No. 32)
32.
A 2 kg object weighs 1.8 kgf on a spring balance. The value of 'g' at that location in m/sec2 is
Discussion:
2 comments Page 1 of 1.
TANMAY SHAH said:
2 years ago
Force = Mass * Acceleration.
F = m g
Here, F = 1.8 kgf = (1.8*9.8) N = 17.64 N.
Now, 17.64 N = 2 kg * g.
So, g = 8.82 m/sec2.
F = m g
Here, F = 1.8 kgf = (1.8*9.8) N = 17.64 N.
Now, 17.64 N = 2 kg * g.
So, g = 8.82 m/sec2.
(2)
Faycz said:
7 years ago
Force = Mass x G.
1.8 kgf (2.204 lbf / 1kgf) (4.4482 N / 1 lbf) = 2 kg (G).
G= 8.8234 m/s2.
1.8 kgf (2.204 lbf / 1kgf) (4.4482 N / 1 lbf) = 2 kg (G).
G= 8.8234 m/s2.
(1)
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