Chemical Engineering - Chemical Engineering Basics - Discussion

Discussion Forum : Chemical Engineering Basics - Section 3 (Q.No. 5)
Heat flow across a hollow sphere of inner radius 'r1' and outer radius 'r2' is directly proportional to
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Baghel said:   7 months ago
From Fourier law.
Q= -kAdt\dr.

Where k is thermal conductivity.
A is the area of the sphere.
dt\dr is a temperature gradient.

The Area of the sphere is 4πr2.
dr/r2 = - 4πKQdt.

Integrated with limit.
We found r1 is the inner radius and r2 outer radius.
r2-r1 = -4πkQ(t1-t2).
Q = 4πr1r2(t1-t2)/r2-r1.

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