Discussion :: Strings - General Questions (Q.No.13)
|Vaishnavi.K said: (Jul 29, 2011)|
|Compare the ASCII value of I and i.|
|Mandar said: (Aug 30, 2011)|
|How can possible that answer please send me reply.|
|Abhitesh Tyagi said: (Sep 20, 2011)|
|As we know that compareTo() compares the current instance with another instance // int n=string.compareTo(s1,s2);
the compare method performs a case sensitive comparison and returns different integer values for different conditionsas under:
. 0 ,if s1 = s2
. 1 ,if s1>s2
. -1 ,if s1<s2
For example if s1="abc" and s2="ABC"
Then n will be assigned a value of -1.because a lowercase letter has a smaller ASCII value than an uppercase letter.
|Kanika Kapoor said: (Nov 1, 2011)|
|If the first string is bigger, the result is 1. If both strings are equal, the result is 0. If the first string is smaller, the result is -1.|
|Rajkumar said: (Dec 27, 2011)|
|No we know that ascii value of A TO Z is 65 to 90 and Ascii value of a To z is 97 to 122 ascii value of I is < i 73<105 so result is 1|
|Uttam Jaiswal said: (Jan 26, 2012)|
|Correct answer is -1 because CompareTo sorts data in ascending order and string s2 comes first with higher value.|
|Anurag said: (Nov 19, 2012)|
|compareTo method in string class used to compare two strings if both were matching it will return one otherwise will return -1.|
|Arun Gupta said: (Apr 8, 2015)|
|Answer is -1 because CompareTo sorts data in ascending order and string s2 comes first with higher value.
0, if s1=s2.
1, if s1>s2.
-1, if s1<s2.
|Sudarshan said: (Jul 4, 2015)|
|As we know that compareTo() compares the current instance with another instance.
c = s1.CompareTo(s2);
s1<s2 then -1.
s1>s2 then 1.
s1 == s2 then 0.
|Soniya said: (Aug 24, 2015)|
|I have one doubt, suppose it is comparing ASCII value of both string.
Then s1 will have greater ASCII value then s2.
So answer will, s1>s2 then 1.
Please give me solution.
|Arvind said: (Oct 19, 2015)|
|I think same @Soniya and my question is same to you?
Please any one give answer.
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