C# Programming - Datatypes - Discussion
Discussion Forum : Datatypes - General Questions (Q.No. 15)
15.
Which of the following statement correctly assigns a value 33 to a variable c?
byte a = 11, b = 22, c;Discussion:
9 comments Page 1 of 1.
Zoltán said:
4 years ago
By adding two-byte values, CLR assumes the sum may be bigger than a type of byte, so it declares the sum variable to int by default. And C is already declared to the type of byte, the explicit conversion is needed.
(1)
Zoltán said:
4 years ago
By adding two-byte values, CLR assumes the sum may be bigger than a type of byte, so it declares the sum variable to int by default. And C is already declared to the type of byte, the explicit conversion is needed.
Venu said:
6 years ago
byte a = 11, b = 22, c;
Here 'a' is declared as byte and 'b' is declared as byte then 'c' is also declared as a byte.
Then why do we need byte conversion for 'c'?
Here 'a' is declared as byte and 'b' is declared as byte then 'c' is also declared as a byte.
Then why do we need byte conversion for 'c'?
Mekala said:
1 decade ago
Can any one explain this question in step by step?
Jatin said:
1 decade ago
This is an example of Type Promotion, viz: All byte and short are promoted to int.
The two correct expressions should be:
1. int c = a+b // If c wasn't declared byte.
2. c = (byte) (a+b) // The question asked.
The two correct expressions should be:
1. int c = a+b // If c wasn't declared byte.
2. c = (byte) (a+b) // The question asked.
Jyothi said:
1 decade ago
Value type means int so why not type cast int. Please any one clarify my doubt?
Ritesh said:
1 decade ago
Can any one have to explain this question in detail?
Jiten said:
1 decade ago
For short and byte types compiler asks for explicit conversion.
The reason is its rule but with common sense that any mathematical calculations can go beyond byte and short types.
The reason is its rule but with common sense that any mathematical calculations can go beyond byte and short types.
Abi said:
1 decade ago
Because the arithmetic expression on the right-hand side of the assignment operator evaluates to int by default.
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