C# Programming - Classes and Objects - Discussion
Discussion Forum : Classes and Objects - General Questions (Q.No. 6)
6.
Which of the following will be the correct output for the C#.NET program given below?
namespace IndiabixConsoleApplication
{
class Sample
{
int i;
Single j;
public void SetData(int i, Single j)
{
i = i;
j = j;
}
public void Display()
{
Console.WriteLine(i + " " + j);
}
}
class MyProgram
{
static void Main(string[ ] args)
{
Sample s1 = new Sample();
s1.SetData(10, 5.4f);
s1.Display();
}
}
}Discussion:
28 comments Page 1 of 3.
Rajeev said:
1 decade ago
It is because the s1.SetData(10, 5.4f); will set the values if i, j but in line s1.Display(); function will call default constructor and default values assigned to i,j (0,0) . that is why it will print 0 0
Narmadha said:
1 decade ago
Here in Line s1.Setdata(10,5.4f);
So Here we called only floating point number, so its displayed 0,0 .
So Here we called only floating point number, so its displayed 0,0 .
Ranjana said:
1 decade ago
Here we did not use the this keyword so that it displayed null values.
Akmal said:
1 decade ago
@Rajeev...
why s1.Display() call default constructor since i and j in same object,s1?
why s1.Display() call default constructor since i and j in same object,s1?
Durg said:
1 decade ago
In this, as s1 is created, default constructor initialize field variable i, j by default value.
i.e, i = 0; j = 0;
-------------
When we are calling s1.SetData(10, 5.4f) , we assign value to local variable i, j; which we define in formal argument ( not field variable )
That's why, compiler generate warning ---
" value is assign to same variable".
-------------
If you want to initialize field variable then
1. use 'this' keyword ,like this.i and this.j
2. use different name for parameter variable.
i.e, i = 0; j = 0;
-------------
When we are calling s1.SetData(10, 5.4f) , we assign value to local variable i, j; which we define in formal argument ( not field variable )
That's why, compiler generate warning ---
" value is assign to same variable".
-------------
If you want to initialize field variable then
1. use 'this' keyword ,like this.i and this.j
2. use different name for parameter variable.
Muthu (VMK) said:
1 decade ago
@ Durg, Well Said.
Until you explain about this Keyword no beginner could understand.
Until you explain about this Keyword no beginner could understand.
Penchala Naidu said:
1 decade ago
Whenever parameters names and instance variables name are same we need to make use of "this" keyword in the method body to refer to instance variables.
Swati mahajan said:
1 decade ago
Answer is 0 0 because not added this in SetData();.
Bhavin said:
1 decade ago
See the argument names and class variable names are same. So it assigns values to argument variables itself and values of class level variables will remain as it is default to 0. When printed it will print those default values 0.
Ramesh Malode said:
1 decade ago
Instance variable name and local variable name of method is same, that's why local variable hide the instance variable, if you want to run this, you should be use "this" keyword as like :
public void SetData(int i, Single j)
{
this.i = i;
this.j = j;
}
If you run without "this" then result remains as zero only.
public void SetData(int i, Single j)
{
this.i = i;
this.j = j;
}
If you run without "this" then result remains as zero only.
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