C Programming - Structures, Unions, Enums - Discussion
Discussion Forum : Structures, Unions, Enums - Find Output of Program (Q.No. 6)
6.
What will be the output of the program ?
#include<stdio.h>
int main()
{
enum status {pass, fail, absent};
enum status stud1, stud2, stud3;
stud1 = pass;
stud2 = absent;
stud3 = fail;
printf("%d %d %d\n", stud1, stud2, stud3);
return 0;
}
Discussion:
24 comments Page 2 of 3.
Nagaraju said:
1 decade ago
How can you say pass0, pass2, pass1 @Sundar.
Amit said:
1 decade ago
@Manu. It is compiler dependent.
Krishna said:
2 decades ago
Because enum values are initialised from zero.
Prasad Deokar said:
1 decade ago
i = 0 1 2.
enum status {pass, fail, absent};
enum status stud1, stud2, stud3;
stud1 = pass; ->0
stud2 = absent; ->2
stud3 = fail; ->1
So 0 2 1
printf("%d %d %d\n", stud1, stud2, stud3);
enum status {pass, fail, absent};
enum status stud1, stud2, stud3;
stud1 = pass; ->0
stud2 = absent; ->2
stud3 = fail; ->1
So 0 2 1
printf("%d %d %d\n", stud1, stud2, stud3);
Ghufran said:
1 decade ago
Simply enum start index from 0 by default if no any value is associated.
Raju Naidu said:
1 decade ago
Hai, If you are declare any variables in enum the default initalization is started from 0 and sequentially they are increasing. So they didn't give any initaliztion in our programm that's why bydefault initaliztion will be takes place.
So pass=0, fail=1, abscent=2.
So pass=0, fail=1, abscent=2.
Sadddd said:
1 decade ago
Good !
Raghu said:
1 decade ago
Thats good explanation XYZ.
You should have write your name anyhow I am fully satisfied with that.
You should have write your name anyhow I am fully satisfied with that.
Sravz said:
1 decade ago
Thank you friends your explanations helped me to get it clear.
Hari said:
1 decade ago
Thanks xyz.
I satisfied with your ans.
I satisfied with your ans.
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